AW: Farbige Zellen zählen
23.04.2007 09:57:02
nighty
hi kurt :-)
alt f11 öffnet den vbeditor
füge den code in ein allgemeines modul
menue anwaehlen einfuegen/funktion/BedingungAdd
=BedingungAdd(A1:A3;3)
3 ist dein farbindex
gruss nighty
Function BedingungAdd(Zellen As Range, farbe As Integer) As Double
Dim Zelle As Range
Dim farben As Integer
Application.Volatile
For Each Zelle In Zellen
farben = GetCellColor(Zelle)
If farben = farbe Then
BedingungAdd = BedingungAdd + 1
End If
Next
End Function
Function GetCellColor(cell As Range) As Integer
Dim i
Dim myVal
Dim myColor As Integer
Dim done As Boolean
On Error Resume Next
Names("testname").Delete
On Error GoTo 0
Application.ReferenceStyle = xlR1C1
myVal = cell.Value
myColor = cell.Interior.ColorIndex
done = False
For i = 1 To cell.FormatConditions.Count
With cell.FormatConditions.Item(i)
If .Type = 1 Then
Select Case .Operator
Case xlBetween
If (myVal >= Evaluate(.Formula1) And myVal = Evaluate(.Formula2)) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlEqual
If myVal = Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlGreater
If myVal > Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlGreaterEqual
If myVal >= Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlLess
If myVal Evaluate(.Formula2) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlNotEqual
If myVal Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
End Select
ElseIf .Type = 2 Then
Names.Add Name:="testname", RefersToR1C1Local:=.Formula1
If Evaluate("testname") Then
myColor = .Interior.ColorIndex
done = True
End If
Names("testname").Delete
Else
MsgBox "Unbekannter Typ: " & .Type, , "PANIC: In
Function GetCellColor"
Exit Function
End If
End With
If done Then Exit For
Next
Application.ReferenceStyle = xlA1
GetCellColor = myColor
End Function